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9x^2-55x+56=0
a = 9; b = -55; c = +56;
Δ = b2-4ac
Δ = -552-4·9·56
Δ = 1009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-\sqrt{1009}}{2*9}=\frac{55-\sqrt{1009}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+\sqrt{1009}}{2*9}=\frac{55+\sqrt{1009}}{18} $
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